Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Su | 5601 | 345 | 1 | 345.0000 |
Esta | 3299 | 232 | 1 | 232.0000 |
Este | 3965 | 221 | 2 | 110.5000 |
Los | 11033 | 749 | 7 | 107.0000 |
Esto | 2011 | 104 | 1 | 104.0000 |
Las | 6598 | 503 | 6 | 83.8333 |
Como | 2053 | 80 | 1 | 80.0000 |
Para | 3021 | 156 | 2 | 78.0000 |
El | 34543 | 1815 | 26 | 69.8077 |
Con | 2424 | 63 | 1 | 63.0000 |
Se | 7742 | 424 | 7 | 60.5714 |
La | 27617 | 1446 | 25 | 57.8400 |
En | 29281 | 478 | 10 | 47.8000 |
Desde | 2274 | 87 | 2 | 43.5000 |
Una | 2856 | 159 | 4 | 39.7500 |
Un | 2645 | 167 | 5 | 33.4000 |
Por | 4179 | 64 | 2 | 32.0000 |
cuales | 1726 | 62 | 2 | 31.0000 |
Cuando | 2397 | 75 | 3 | 25.0000 |
De | 3545 | 90 | 4 | 22.5000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
dentro | 2090 | 2 | 73 | 0.0274 |
junto | 2771 | 3 | 61 | 0.0492 |
alrededor | 1553 | 2 | 39 | 0.0513 |
millones | 2310 | 8 | 145 | 0.0552 |
convertirse | 511 | 1 | 17 | 0.0588 |
debido | 2901 | 4 | 65 | 0.0615 |
falta | 815 | 1 | 15 | 0.0667 |
capaz | 669 | 1 | 14 | 0.0714 |
conde | 205 | 1 | 14 | 0.0714 |
cerca | 1486 | 3 | 40 | 0.0750 |
posibilidad | 535 | 1 | 12 | 0.0833 |
capaces | 301 | 1 | 12 | 0.0833 |
énfasis | 124 | 1 | 12 | 0.0833 |
miles | 295 | 1 | 11 | 0.0909 |
rara | 148 | 1 | 11 | 0.0909 |
Provincial | 165 | 2 | 20 | 0.1000 |
enamorado | 121 | 1 | 10 | 0.1000 |
finales | 1363 | 3 | 27 | 0.1111 |
detrás | 463 | 2 | 18 | 0.1111 |
relacionada | 137 | 1 | 9 | 0.1111 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II